That's because it's much smaller and it's near the equator line.
It shows this:Ĭurved fence and horizon obviously are unwanted, but the sun is still quite round. (sorry for the glosses, my freeware CAD program doesn't allow editing the lights)Īffinity Photo has Layer > Live Projection > Equirectangular which can show the wiew inside the sphere like the image were painted onto the inside surface of the sphere and the observer is in the midpoint. On a sphere seen from outside it is this: If you accept some distortion, You simply increase the canvas size to 400%
#Convert panorama to photosphere full#
I guess you wantġ) an equirectangular image which presents a sphere with your image as a part of the surface, no need to cover full sphere with itĢ) when one watches it sitting in the middle of the sphere, he can see your image on the sphere without distortion and in so big size that the image covers a substatial part of the field of vision, say a sector 90 degrees wide and 45 degrees high. I think you see this as an useless piece of math sophistry, you expected something else. As you see, top and bottom edges of your image are pinched to points, the poles. Half of the image is hidden behind the sphere, but there it is. Seemingly the proportions are 2:1, so it is equirectangular already if the corresponding sphere is this: You wanted to convert your image to equirectangular. That reflects the fact the distance between the poles along the sphere is exactly half of the full round trip along the equator. Top and bottom edges contain actually only single points - the poles. The more stretching the further the point is from the equator. There's no stretching on the equator, but the the image is stretched horizontally elsewhere. In the left there's a spherical map and in the right there's the equivalent plane map, the equirectangular projection from sphere to a rectangle. Equirectangular image presents a sphere, it's distorted so that meridians and parallels on the sphere are shown as straight vertical and horizontal lines.
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